Design HashSet
Design a HashSet without using any built-in hash table libraries.
Implement MyHashSet
class:
void add(key)
Inserts the valuekey
into the HashSet.bool contains(key)
Returns whether the valuekey
exists in the HashSet or not.void remove(key)
Removes the valuekey
in the HashSet. Ifkey
does not exist in the HashSet, do nothing.
Example 1:
Input ["MyHashSet", "add", "add", "contains", "contains", "add", "contains", "remove", "contains"] [[], [1], [2], [1], [3], [2], [2], [2], [2]] Output [null, null, null, true, false, null, true, null, false] Explanation MyHashSet myHashSet = new MyHashSet(); myHashSet.add(1); // set = [1] myHashSet.add(2); // set = [1, 2] myHashSet.contains(1); // return True myHashSet.contains(3); // return False, (not found) myHashSet.add(2); // set = [1, 2] myHashSet.contains(2); // return True myHashSet.remove(2); // set = [1] myHashSet.contains(2); // return False, (already removed)
Constraints:
0 <= key <= 106
- At most
104
calls will be made toadd
,remove
, andcontains
.
import bisect
class MyHashSet:
def __init__(self):
self.size = 107
self.arr = [[] for i in range(self.size)]
def hfn(self, key):
key = ((key >> 16) ^ key) * 0x45d9f3b
key = ((key >> 16) ^ key) * 0x45d9f3b
key = (key >> 16) ^ key
return key % self.size
def add(self, key: int) -> None:
pos = bisect.bisect_left(self.arr[self.hfn(key)], key)
if pos >= len(self.arr[self.hfn(key)]) or self.arr[self.hfn(key)][pos] != key:
self.arr[self.hfn(key)].insert(pos, key)
def remove(self, key: int) -> None:
pos = bisect.bisect_left(self.arr[self.hfn(key)], key)
if pos < len(self.arr[self.hfn(key)]) and self.arr[self.hfn(key)][pos] == key:
del self.arr[self.hfn(key)][pos]
def contains(self, key: int) -> bool:
pos = bisect.bisect_left(self.arr[self.hfn(key)], key)
if pos < len(self.arr[self.hfn(key)]) and self.arr[self.hfn(key)][pos] == key:
return True
return False
# Your MyHashSet object will be instantiated and called as such:
# obj = MyHashSet()
# obj.add(key)
# obj.remove(key)
# param_3 = obj.contains(key)
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