Minimum Consecutive Cards to Pick Up
You are given an integer array cards
where cards[i]
represents the value of the ith
card. A pair of cards are matching if the cards have the same value.
Return the minimum number of consecutive cards you have to pick up to have a pair of matching cards among the picked cards. If it is impossible to have matching cards, return -1
.
Example 1:
Input: cards = [3,4,2,3,4,7] Output: 4 Explanation: We can pick up the cards [3,4,2,3] which contain a matching pair of cards with value 3. Note that picking up the cards [4,2,3,4] is also optimal.
Example 2:
Input: cards = [1,0,5,3] Output: -1 Explanation: There is no way to pick up a set of consecutive cards that contain a pair of matching cards.
Constraints:
1 <= cards.length <= 105
0 <= cards[i] <= 106
class Solution:
def minimumCardPickup(self, cards: List[int]) -> int:
n = len(cards)
pos = {}
minDiff = float('inf')
for i in range(n):
if cards[i] in pos:
minDiff = min(minDiff, i - pos[cards[i]] + 1)
pos[cards[i]] = i
if minDiff == float('inf'):
return -1
return minDiff
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