Max Consecutive Ones

Given a binary array nums, return the maximum number of consecutive 1's in the array.

 

Example 1:

Input: nums = [1,1,0,1,1,1]
Output: 3
Explanation: The first two digits or the last three digits are consecutive 1s. The maximum number of consecutive 1s is 3.

Example 2:

Input: nums = [1,0,1,1,0,1]
Output: 2

 

Constraints:

  • 1 <= nums.length <= 105
  • nums[i] is either 0 or 1.
SOLUTION:
class Solution:
    def findMaxConsecutiveOnes(self, nums: List[int]) -> int:
        nums.append(-1)
        maxOnes = 0
        curr = 0
        for num in nums:
            if num <= 0:
                maxOnes = max(maxOnes, curr)
                curr = 0
            else:
                curr += 1
        return maxOnes

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