Count the Number of Consistent Strings

You are given a string allowed consisting of distinct characters and an array of strings words. A string is consistent if all characters in the string appear in the string allowed.

Return the number of consistent strings in the array words.

 

Example 1:

Input: allowed = "ab", words = ["ad","bd","aaab","baa","badab"]
Output: 2
Explanation: Strings "aaab" and "baa" are consistent since they only contain characters 'a' and 'b'.

Example 2:

Input: allowed = "abc", words = ["a","b","c","ab","ac","bc","abc"]
Output: 7
Explanation: All strings are consistent.

Example 3:

Input: allowed = "cad", words = ["cc","acd","b","ba","bac","bad","ac","d"]
Output: 4
Explanation: Strings "cc", "acd", "ac", and "d" are consistent.

 

Constraints:

  • 1 <= words.length <= 104
  • 1 <= allowed.length <= 26
  • 1 <= words[i].length <= 10
  • The characters in allowed are distinct.
  • words[i] and allowed contain only lowercase English letters.
SOLUTION:
class Solution:
    def countConsistentStrings(self, allowed: str, words: List[str]) -> int:
        allowed = set(allowed)
        ctr = 0
        for w in words:
            if set(w).issubset(allowed):
                ctr += 1
        return ctr

Comments

Post a Comment

Popular posts from this blog

Encrypt and Decrypt Strings

You are given a character array keys containing unique characters and a string array values containing strings of length 2. You are also given another string array dictionary that contains all permitted original strings after decryption. You should implement a data structure that can encrypt or decrypt a 0-indexed string. A string is encrypted with the following process: For each character c in the string, we find the index i satisfying keys[i] == c in keys . Replace c with values[i] in the string. Note that in case a character of the string is not present in keys , the encryption process cannot be carried out, and an empty string "" is returned. A string is decrypted with the following process: For each substring s of length 2 occurring at an even index in the string, we find an i such that values[i] == s . If there are multiple valid i , we choose any one of them. This means a string could have multiple possible strings it can decrypt t...
Read more

Degree of an Array

Given a non-empty array of non-negative integers nums , the degree of this array is defined as the maximum frequency of any one of its elements. Your task is to find the smallest possible length of a (contiguous) subarray of nums , that has the same degree as nums .   Example 1: Input: nums = [1,2,2,3,1] Output: 2 Explanation: The input array has a degree of 2 because both elements 1 and 2 appear twice. Of the subarrays that have the same degree: [1, 2, 2, 3, 1], [1, 2, 2, 3], [2, 2, 3, 1], [1, 2, 2], [2, 2, 3], [2, 2] The shortest length is 2. So return 2. Example 2: Input: nums = [1,2,2,3,1,4,2] Output: 6 Explanation: The degree is 3 because the element 2 is repeated 3 times. So [2,2,3,1,4,2] is the shortest subarray, therefore returning 6.   Constraints: nums.length will be between 1 and 50,000. nums[i] will be an integer between 0 and 49,999. SOLUTION: from collections import defaultdict class Solution : def findShortestSubArr...
Read more

Minimum Sum of Four Digit Number After Splitting Digits

You are given a positive integer num consisting of exactly four digits. Split num into two new integers new1 and new2 by using the digits found in num . Leading zeros are allowed in new1 and new2 , and all the digits found in num must be used. For example, given num = 2932 , you have the following digits: two 2 's, one 9 and one 3 . Some of the possible pairs [new1, new2] are [22, 93] , [23, 92] , [223, 9] and [2, 329] . Return the minimum possible sum of new1 and new2 .   Example 1: Input: num = 2932 Output: 52 Explanation: Some possible pairs [new1, new2] are [29, 23], [223, 9], etc. The minimum sum can be obtained by the pair [29, 23]: 29 + 23 = 52. Example 2: Input: num = 4009 Output: 13 Explanation: Some possible pairs [new1, new2] are [0, 49], [490, 0], etc. The minimum sum can be obtained by the pair [4, 9]: 4 + 9 = 13.   Constraints: 1000 <= num <= 9999 SOLUTION: class Solution : def minimumSum ( self,...
Read more